A few days ago
probability question! Please Help!?
AT&T claims that when customers call directory assistance for telephone numbers, the right number is given 90% of the time. Assume 90% rate of correct responses. What is the probability that among 5 requests, 3 of them are correct? (Adapted from Triola, 2000)
Top 2 Answers
A few days ago
Favorite Answer
Use the binomial formula:
(p + q)^5 =
p^5 + 5p^4q + 10p^3q^2 + 10p^2q^3 + 5pq^4 + q^5
p = .90
q = .10
P(3) = 10p^3q^2
P(3) = 10 * (.9)^3(.1)^2
P(3) = 10 * (.729) * (.01) = .0729 or 7.29%
Good luck in your studies,
~ Mitch ~
This website will calculate the probabilities for you:
http://stattrek.com/Tables/Binomial.aspx
There’s also a powerpoint file covering this problem:
http://staff.wtn.k12.sd.us/fairchis/powerpoints/book%204-3.ppt
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A few days ago
If for sure 90 is the rate of correct reponses then theoretically the probability is 100% – THEORETICALLY. This is because 90% of 5 is 4.5 and 4.5 < 3 which means that, because the rate of correct answers is 90% the probabilty of any percentage of 5 under 90% being correct is 100%. So that is your answer.
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