Since there are 5 suspects (let’s say Suspects V-Z), the odds of randomly picking any of them is (1/5). So Victim A has a one in five chance of choosing Suspect X.

Now, Victim B will *independently* select Suspect X with the same probability: one out of five times. You multiply his 1/5 probability by the 1/5 probability of Victim A.

In other words, out of 25 identifications, Victim A would choose Suspect X 5 times (for 5/25 or a one in five probability), and of those 5 times, Victim B would independently choose Suspect X only 1 out of the 5 times (same probability). It would therefore take 25 rounds of identification for them to *both* randomly choose Suspect X at the same time.

Based on that pattern, figure out how many rounds of identification it would take to get 9 people to all choose the same guy out of the lineup of 5 suspects. (It’s near 2 million, as KAL said)