distance = sqrt(x2-x1)^2+(y2-y10^2)=34

x1=-21 y1=? x2=5 y2=-14

(-14-y1)^2 + (5 -(-21))^2 =34^2

196+28y1+y1^2 +26^2 = 34^2

196+28y1+y1^2+676=1156

y1^2+28y1-284=0

solving, y1=7.9 or -35.9

right this is a thank you to remedy utilising row-decrease x + y + z = 7 3x – 2y + z = 3 x + 6y + 3z = 25 a million a million a million | 7 3 -2 a million | 3 a million 6 3 | 25 R2 = R2 – 3 * R3 a million a million a million | 7 0 -20 -8 | -seventy two a million 6 3 | 25 R3 = R3 -R1 a million a million a million | 7 0 -20 -8 | -seventy two 0.5 2 | 18 R3 = R3 + a million/4 * R2 a million a million a million | 7 0 -20 -8 | -seventy two 0 0 0 | 0 R1 = R1 + a million/20 * R2 a million 0 .6 | 3.4 0 -20 -8 | -seventy two 0 0 0 | 0 R2 = -R2/20 a million 0 .6 | 3.4 0 a million .4 | 3.6 0 0 0 | 0 So the perfect constraints are that: x + .6z = 3.4 y + .4z = 3.6 case in point, recommendations contain: x = a million a million + .6z = 3.4 .6z = 2.4 z = 4 y + .4z = 3.6 y + a million.6 = 3.6 y = 2 x = a million, y = 2, z = 4 x = 2 2 + .6z = 3.4 .6z = a million.4 z = 2.33.. y + .4(2.33..) = 3.6 y = 2.sixty six x = 2, y = 2.sixty six, z = 2.33