Here’s what I did so far: I found the slope of the 2 lines. For Ln1 I got a slope of (3/5) and for Ln2 I got a slope of 7. Then I wrote the equation for each line. Ln1 I has the equation y+4= (3/5)x. Ln2 I has the equation y-1=7x. I used point-slope form for both of these equations. Next, I set up the Point to Line formula. So I have:

ab. value (3x-5y-20) divided by the sq. root of 3sq + 5sq.

EQUALS

ab. value (7x-y+1) divided by the sq. root of 7sq + 1sq.

Now this is where I’m confused. In the example that my teacher showed us, the lines were perpendicular and the bottom of the equations were equal, so they crossed out. But in this problem, the lines aren’t perpendicular, and the bottoms of the equation work out to be RADICAL 34 and RADICAL 50.

So my question is (if you understand all of that) how do you do the problem from there? Or did I just mess the whole problem up? Please Help!