A few days ago
Anonymous

Point (k,-2) lies on the line whose equation is x-3y=7. What is the value of K?

Point (k,-2) lies on the line whose equation is x-3y=7. What is the value of K?

Top 6 Answers
A few days ago
BLT (coolest initials ever)

Favorite Answer

sorry. i won’t give you the answer. ๐Ÿ˜› but i’ll explain it. ๐Ÿ˜€

plug the y-value (-2) into the equasion, and solve for x.

x=k

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A few days ago
dagiffy
k = 1
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4 years ago
Anonymous
bear in suggestions, ok is your “x” and x – 3y = 7 is in customary style, so which you may desire to transform it to customary slope-intercept style. In different words, sparkling up the equation for y. you may desire to have: (-7/3) + (x/3) = y this means your slope is one million/3 and your y-intercept is -7/3. Plug interior the y and sparkling up for ok. y = mx + b -2 = (one million/3)x – (7/3) -2 + (7/3) = (one million/3)x (-2 + (7/3)/(one million/3) = x Dividing via a fragment is the comparable as multiplying the amazing and backside via the denominator. this could desire to do away with the fractions and you may desire to have: -2 + 7 = x x/ok = 5
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A few days ago
Kay B
k is the x co ordinate -2 is the y-coordinate

x-3y=7

so we substitute y= -2 andx= k

k-3(-2)=7

k+6=7

k=7-6

k=1

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A few days ago
Anonymous
first answer did a nice job explaining it.

the answer is x + 6= 7

x=1

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A few days ago
Elayna D
easy sub in -2 for k

K (or x) = 1

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