Please help with math word problem, Im going to throw my notebook out the window!?
An electrician, a carpenter, and a plumber are hired to work on a house. The electrician earns $25 per hour. The carpenter $27 per hour, and the plumber $33 per hour. On the first day on the job the three worked a total of 23.75 hours and earned a total of $689.25. If the plumber worked 2.25 more hours than the carpenter did, then how many hours did the electrician work?
Please help me out on this, from my other posts, it’s obvious math is my weak subject…
Favorite Answer
p = c + 2.25, so p + c = 2c + 2.25
e = 23.75 – 2c – 2.25 = 21.5 – 2c, so
689.25 = 25(21.5 – 2c) + 27c + 33(c + 2.25), and
689.25 = 537.5 – 50c + 27c + 33c + 74.25, or 10c + 611.75.
Then 10c = 77.5, and c = 7.75, and e = 6
25e + 27c + 33p = 689.25
p = 2.25 + c so…
25e + 27c + 33(2.25+c) = 689.25
25e + 27c + 74.25 +33c = 689.25
25e + 60c = 615
23.75 = e + c + p
23.75 = e + c + 2.25 + c
21.50 = e + 2c
e = 21.50 – 2c
so…back to the previous one…
25e + 60c = 615
25 (21.50-2c) + 60c = 615
537.5 – 50 c + 60 c = 615
10c = 77.5
c = 7.75
so…
e = 21.50-2c
e = 21.50 – (2*7.75)
e = 21.5 – 15.5
e = 6
so, the electrician works for 6 hours.
the hours each one worked,will be a,b,and c.
_____________________________________
a+b+c=23.75hours. (1)
25a+27b+33c=689.25$ (2)
c=b+2.25 (3)
now,u will put (3)into (1):
a+b+b+2.25=23.75
a+2b=21.5 ==>a=21.5-2b (4)
now you will put (4) & (3) into (1) and you will find b.
then go to (4),plug in the result that you’ve found for b and you will have a…..
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