You’ll find the solution on this link.

Question is the same.

http://www.algebra.com/cgi-bin/embed-solution.mpl?show=1&solution=63884

http://www.algebra.com/algebra/homework/Rectangles/Rectangles.faq.question.87998.html

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Well the rectangle has its length once centimeter longer then its width. The width is 4cm while the length is 5cm. See look at the diagonal line and see how it fits the width when you bring it up or down? The diagonal lines shows the width but just diagonally.

Using Pythagorean Theorem, I got the answer 2.284 cm and 3.284 cm.. I just don’t know which is the length or the width.. Also, the values are rounded off… I’m not really sure about this..

Denote the width by x, then the length is (x+1).

By Pythagorean theorem we have:

x^2 + (x+1)^2 = 4^2

or

2x^2 + 2x + 1 = 16

or

2x^2 + 2x – 15 = 0

Solving this quadratic euation we find (only positive root counts): x = (-1+sqrt(31))/2

So

width = (-1+sqrt(31))/2

length = (-1+sqrt(31))/2 + 1 = (1+sqrt(31))/2

to clean up the equation you’re able to desire to positioned all words in s variable in one element of the equation and the words regarding merely organic numbers on the different: in the beginning, you progression the term 0.5s from the suited to the left element changing its sign, from + to -. you progression additionally the extensive form 5 from the left to the suited element and additionally exchange its sign from + to -. 0.75s-0.50s=9-5 2d, on the grounds which you have all words in s on the left element and all numbers on the suited element you are able to hold out the mathematical operations indicated. 0.25s=4 Now, you have the extensive form 0.25 multiplying s on the left element, you are able to bypass it to the different element the place it is going do carry out the different mathematical operation, for this reason, branch. s=4/0.25 s=sixteen the respond is: sixteen songs.

how will you know if its the correct answer?