A few days ago

# Please help?

The length of a rectangle is 1 cm longer than its width. If the diagonal

of the rectangle is 4 cm, what are the dimensions (the length and the width) of the

rectangle?

Top 3 Answers

A few days ago

Favorite Answer

(a+b)^2 = c^2 where c is the hypotenuse of the triangle

a=x b= x+1

(x+(x+1))^2=16

(2x)^2 + 1 ^2 =16

4x^2 +1 =16

-1 -1

4x^2 =15

/4 /4

x^2 = 3.75

x = 1.936

1.94 cm and 2.94 cm

or 2 cm and 3 cm

depending on how accurate you need to be

hope this helps

0

A few days ago

the length is x+1 and the width will be x.

since the diagonal is the hypotenuse of a right triangle formed with the length and width, the pythagorian (spelling) theorum can be used, 4^2 = x^2 + (x+1)^2

16 = x^2 + x^2 + 2x + 1 or 2x^2 + 2x +1 = 16

by the quadratic formula x = [1 + (square root) 30]/ 2

and length is that + 1

0

A few days ago

3cm x 2cm

0

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