A few days ago
physics home work please help?
A ball is thrown upward from the ground with an initial speed of 31 m/s. At the same instant, a ball is dropped from rest from a building 15 m high. After how long will the balls be at the same height?
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I graphed the movement of the two objects and put the point of intersection as the answer, but the webassign.net program said it was wrong. What do I have to do to solve this
Top 1 Answers
A few days ago
Favorite Answer
what answer DID you get? (that would help with answering your Q).
did you use the following equation for height vs. time?
y = yo + vo*t – (1/2)g*t^2
where g = 9.81 m/s
1st ball:
yo = 0 m
vo = +31 m/s
2nd ball
yo = 15 m
vo = 0 (from rest)
so: y1 = 31t – (1/2)gt^2
y2 = 15 – (1/2)gt^2
set them equal to each other .. that’s when they are at the same height.
….and solve for t.
g.l.
d
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