2nd term: 2/3

3rd term: 3/4

4th term: 4/5

5th term: 5/6

Think…………….

9th term: 9/10

10th term: 10/11

19th term: 19/20

Think…………….

31st term: 31/32

43rd term: 43/44

58th term: 58/(58+1)

73rd term: 73/(73+1)

Think……………

nth term: n/(n+1)

Similarly, but you may findthis a little easier if you understood the last example:

1st term: 1/3

2nd term: 2/5 = 2/(3+2)

3rd term: 3/7 = 3/(3+2+2)

4th term: 4/((3+2+2+2) = 4/9

5th term: 5/(3 plus FOUR 2`s) = 5/11

9th term: 9/(3+8*2) = 9/19

nth term = n/(3+2(n-1))

= n/(2n+1)

Hope this helps, Twiggy.

for the first one that pattern can be described as n/(n+1)

for the second one it’s a bit more complex. it’s n/(2n+1)

Hope this helps you understand this type of problem better

2nd question: the n”th term = n/(2n+1)

=)