5(2+7)

One way to do this would be to add the 2 and 7 first.

= 5(9)

Then multiply

= 45

Are you following so far?

Another way would be to use the distributive property.

5(2+7)

= 5(2) + 5(7)

= 10 + 35

= 45

Still following?

There is no extra 5. The five goes with the 2 and the 7.

If it was only suppose to go with the two, then it would be written this way

5(2) + 7

This gives you 10+7 = 17

See the difference? I hope this helps.

#1

4(x-3) = 4(x) + 4(-3) = 4x – 12

#2

5(x-6) = 5(x) + 5(-6) = 5x – 30

#3

6(2+4x) = 6(2) + 6(4x) = 12 + 24x

#4

-5(2x-7) = (-5)(2x) + (-5)(-7) = -10x + 35

#5

7p(2q-3) + 4q(3-3p)

= 7p(2q) + 7p(-3) + 4q(3) + 4q(-3p)

= 14pq – 21p + 12q – 12pq

Combine like terms (You can combine 14pq and -12pq).

= 2pq – 21p + 12q

you need to multiply 5 to 2x and you need to multiply 5 to 7. and thats when you get 10x+35.

exmaple if yu havethe equeation 5(2x+7+3y) then the solution would be 5 times 2x, 7 times 5 and 5 times 3y

10x+35+15y.

you need to distribute the multiplicand to the quantity in parethesis