more math…?
2.)right each number as a product of prime numbers
a.)620
b.)260
286 athlets are divided into 18 teams as evenly as possible.how many athlets are on each team?
Favorite Answer
2). For this problem you have to prime factorize the numbers so……620 so the answer would be 2*2*5*5*7. Now do the same thing for 260 so the answer is 2*2*5*13
620 260
/ \ / \
2 310 2 130
/ \ / \
2 155 2 65
/ \ / \
5 35 5 13
/ \
7 5
As for the last one I can’t answer.
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