A few days ago

Anonymous

Maths problem: find x?

16^x – 12(4^x) + 32 = 0

Top 3 Answers

A few days ago

nikred

Favorite Answer

trust me the second answer is wrong……he got lucky becos the answer is 1. the right approach is write 16^x as 4^2x or (4^x)^2,

(4^x)^2-12(4^x)+32=0

then u substitute 4^x as lets say y

then we have y^2-12y+32=0

now solve it y^2-8y-4y+32=0

y(y-8)-4(y-8)=0

(y-8)(y-4)=0

Y=4 or 8

therefore asy=4^x=4 or 8

4^x=4, x=1

4^x=8

take log on both sides

log 4^x=log 8

xlog4=log8

x=log8/log4=1.5

therefore x=1 and 1.5

u can check it if you want to

A few days ago

antoniacaraveteanu

A few days ago

htv33

First you need to do some simplifying:

16^x – 12(4^x) + 32 =0 would be….

16^x – 48^x + 32 =0 which simplifies to….

-32^x + 32 =0 which leads us to ….

x = 1 becasue -32 + 32 is 0

please help me !!!?

Children in Distress.?

Can you help me write a persuasive speech in less than two hours?

whats a great website for the middle colonies?

find the intersection of x^2+y^2=16 and y=x+10?

Any suggestions on a famous person?