A few days ago
Maths dum question.?
An examination consists of 3 papers. The minimum total score required to pass the examination is (8x+4y) marks. James scores (2x-y+10) marks and ( 2x+3y-6) marks in the first 2 paper.
a. Find james’ total score in the first 2 papers.
b.How many marks does james’ score in the third paper if he just passes the examination?
THX!!!!!!!!!
Top 1 Answers
A few days ago
Favorite Answer
a) James’ total score is just the sum of his two marks:
(2x-y+10) + (2x+3y-6)
= 2x+2x +-y+3y +10-6
= 4x +2y+4
b) Let S= the score he needs in the 3rd paper, then the total scores must equal the required score:
4x+2y+4 +S = 8x+4y
isolate S on one side:
S = 8x+4y – (4x+2y+4)
= 8x +4y -4x -2y -4
= 4x +2y -4
That’s it!
0
- Academic Writing
- Accounting
- Anthropology
- Article
- Blog
- Business
- Career
- Case Study
- Critical Thinking
- Culture
- Dissertation
- Education
- Education Questions
- Essay Tips
- Essay Writing
- Finance
- Free Essay Samples
- Free Essay Templates
- Free Essay Topics
- Health
- History
- Human Resources
- Law
- Literature
- Management
- Marketing
- Nursing
- other
- Politics
- Problem Solving
- Psychology
- Report
- Research Paper
- Review Writing
- Social Issues
- Speech Writing
- Term Paper
- Thesis Writing
- Writing Styles