A few days ago
Anonymous

mathematics problem.?

Help needed.

Q26) Simplify this fraction.

(6x² – x -2) / (9x² + 6x – 8) multiply (2x² – 5x – 12) / (4x² + 4x – 3) Devide (2x² – 7x – 4) / (6x² + 5x – 4).

Help needed.

Q27) Simplify this fraction.

(x² + 18x + 80) / (x² + 15x + 56) Devide (x² + 5x – 50) / (x² + 6x – 7) Devide (x – 1 / x – 5).

Top 3 Answers
A few days ago
Kia

Favorite Answer

Q26) [(6x² – x – 2) / (9x² + 6x – 8)] * [(2x² – 5x – 12) / (4x² + 4x – 3)] / [(2x² – 7x – 4) / (6x² + 5x – 4)]

= [(3x – 2)(2x + 1) / (3x – 2)(3x + 4)] * [(2x + 3)(x – 4) / (2x + 3)(2x – 1)] / [(2x + 1)(x – 4) / (2x – 1)(3x + 4)]

= [(2x + 1) / (3x + 4)] * [(x – 4) / (2x – 1)] / [(2x + 1)(x – 4) / (2x – 1)(3x + 4)]

= [(2x + 1)(x – 4) / (3x + 4)(2x – 1)] / [(2x + 1)(x – 4) / (2x – 1)(3x + 4)]

= [(2x + 1)(x – 4) / (3x + 4)(2x – 1)] * [(2x – 1)(3x + 4) / (2x + 1)(x – 4)]

= [(2x + 1)(x – 4)(2x – 1)(3x + 4) / (3x + 4)(2x – 1)(2x + 1)(x – 4)]

= 1

Q27) [(x² + 18x + 80) / (x² + 15x + 56)] / [(x² + 5x – 50) / (x² + 6x – 7)] / [(x – 1 / x – 5)]

= [(x + 10)(x + 8) / (x + 7)(x + 8)] / [(x + 10)(x – 5) / (x + 7)(x – 1)] / [(x – 1 / x – 5)]

= [(x + 10) / (x + 7)] / [(x + 10)(x – 5) / (x + 7)(x – 1)] / [(x – 1 / x – 5)]

= [(x + 10) / (x + 7)] * [(x + 7)(x – 1) / (x + 10)(x – 5)] / [(x – 1 / x – 5)]

= [(x + 10)(x + 7)(x – 1) / (x + 7)(x + 10)(x – 5)] / [(x – 1 / x – 5)]

= [(x – 1) / (x – 5)] / [(x – 1 / x – 5)]

= [(x – 1) / (x – 5)] * [(x – 5 / x – 1)]

= [(x – 1)(x – 5) / (x – 5)(x – 1)]

= 1

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A few days ago
Anonymous
Q26) Answer 1

no time to do q27

try to factorise all the expressions..zey will cancel out by themselves..

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A few days ago
Ghost
Q26 ans is 8

Q2 ans is 6

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