when you distribute the negative it becomes…

c+3-2c-1+2c=4

combine like terms -2c+2c+c the 2c’s canceled each other out =)

you’re left with….

c+2=4

get the 2 on the other side so the variable is alone

c=4-2

c = 2

good job =)

c+3-2c-1+2c=4

add or subtract like terms

2+c=4

c=4-2

c=2

You got it right

By solving steps by steps, you should get:

(c + 3) – 2c – (1 – 2c) = 4

-> c+3-2c-1+2c=4

-> c-2c+2c+3-1=4 <---put all the like terms together ->1c+2=4

->1c=4-2

->1c=2

Since 1c=c; therefore, c=2

(c+3)-2c-1+2c=4

c+3-2c-1+2c=4

c-2c+2c+3-1=4

c+2=4

c=4-2

c=2

That was easy…(you can replace the solution c=2 in the original ecuation and will match i did it.

the 2cs cancel each othe rout

(c + 3) – 2c – (1 – 2c) = 4

c + 3 – 2c – 1 + 2c = 4

c + 2 = 4

c=2

Ali

c + 3 – 2c – 1 + 2c = 4

c + 2 = 4

c = 2

Good job.

(2 + 3) – 2(2) – (1 – 2[2]) = 5 – 4 – (-1)(2)

=1 – (-2)

= 3

Nope, 2 is not the answer..

(2+3)-2(2)-(1-2(2))=4

5-4-(-3)=4

1–3=4

4=4

yup.