if one angle on a parallelogram is 68 degrees, then there exists another angle on that same parallelogram with 68 degrees. You know this because if you extend the parallel lines on a parallelogram, you produce alternate interior angles. The two degrees are the same.

the total number of degrees in a parellogram (which has 4 sides and 4 angles) is 360 degrees

360 – 68 – 68 = 224

the total of the other two angles is 224 degrees

the other two angles are the same as each other so divide by 2

224 / 2 = 112

the answer is 68, 112, 112 degrees

Answer: 68, 112, 112

A parallelogram is a 4 sided figure so the angles equal 360 degrees. Also in a parallelogram, the opposite angles are congruent (so you know one other angle is 68). If you add 68 + the other 68 you get 136. Subtract that from the total angle which is 360 and you get 224. Now there has to be 2 same angles that equal 224 so just divide by 2 and you get your 2 last angles.

The interior angles of any quadrilateral always add up to 360 degrees.

Also, in a parallelogram, there are two sets of equal interior angles. The angles opposite each other are equal.

So, if you have one angle equalling 68, you must have another that also equals 68.

68(2) = 136

360 – 136 = 224

Since the last two angles must be equal, just divide 224 by 2.

224/2 = 112

Your angle measures are 68, 68, 112, and 112.

Well since one side is 68 degrees,so is the opposite,So thats 136 degrees all together.Now the total degrees in a parrolellogram is 360 so,360-136=224.You have two angles left,so divide 224 for by 2,and you have 112.Therefore,2 angles are 112,and the other 2 are 68 degrees.

i’m going to objective to describe the suitable i will: initially, everytime you prefer to clean up for a variable (for that reason x), you’re able to placed the variable on one area and the different numbers on the different. So first placed the x on the left area of the equation. to try this, you will word that x is damaging (-x). because of this, to stability the equation, you upload effective x to the two area: 5 + x = 8 – x + x Now, you recognize that -x + x equals 0, so which you will now take that out of the equation: 5 + x = 8 Now you’re able to placed the 5 on the main suitable area so x could be on my own. you recognize that 5 is a favorable sort (+5), with a view to stability the equation, you subtract 5 on the two area: 5 – 5 + x = 8 – 5 5 – 5 equals 0, so which you will now take that out of the equation: x = 8 – 5 you may now clean up x particularly. x = 3 So this suggests the suited answer is x = 3 If we plug in 3 to the equation, we will se that that’s real. 5 = 8 – 3 5 = 5 i wish this helps =)

well there is 360* in a parrelogram you just divide by 3 and you figure if each angle is more or less