math help please?
A)B(-1.5,5)
B) B(3,-1)
C) B(-6,11)
D) B(1.5,2)
2. Solve for the value of y and the measures of angles 1 and 3. Please show work. One of the lines crosses another line to form four angles labeled clockwise 1,2,3, and 4. The measures of these angles are:
(angle 1)M<1 = (6y +29) (angle 2)M<2 = (4x+31) (angle 3)M<3 = (1 2y -7) (angle 4)M<4 = (6x - 11 )
Favorite Answer
let the mid point cordinate be (x,y)
and we are given A(0,3) And M (-3,7)
so we will find by using x={0+(-3)}/2=-3/2
y={3+7}/2=10/2=5
Hence, the cordiantes are (x,y) is (3/2,5)
question no.2—The angles are having 2 pairs of vertically opposite angles.
If you draw a cross then label the angles ,you will find that 1&3 ,2&4 are facing each other.
the property applied here is that these two pairs are vertically opposite angles.they are equal to one another,hence 1=3 and 2=4
so,(6y +29)=(12y -7)
6y-12y=-7-29
-6y=-36
y=6
similarly,(4x+31)=(6x – 11 )
4x-6x=-11-31
-2x=-42
x=21
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