b. m = (y2 – y1)/(x2 – x1)

m = (2 – 0)/(2 – 3)

m = 2/ -1

m = -2

Slope-intercept form is y = mx + b. Substitute and solve:

0 = -2(3) + b

0 = -6 + b

b = 6

So the equation is y = -2x + 6. The general form is 2x + y = 6, and I think the point-slope form is x = (6 – y)/2. (Don’t hold me to it, I don’t remember point-slope being taught. The others are true.)

c. (2x – 3)/5 + 2 <= 6x - 4 (2x - 3)/5 <= 6x - 6 2x - 3 <= 30x - 30 2x <= 30x - 27 -28x <= -27 x >= 28/27

For the second problem, it is just like a normal equation, only with a different sign. In the end, you should get

x is greater than or equal to 3/28.