I’m in 9th grade, close enough, should be able to help you.

Okay, just so you know, for future reference, ^2 means power two.

Secondly, are you sure there is no equal sign? If not, I’m just going to assume you have to factor these equations.

1) 6x^2 – 2x + 5x – 3

Okay, you’ve got your equation. Lets combine like terms first.

6x^2 + 3x – 3

Factor out the 3.

3(2x^2 + x – 1)

Okay, you’ve got something you can factor out of the expression in the parentheses.

3(2x – 1)(x + 1)

There! That’s your answer, you can factor it no more.

2) 5 – 7x + 3x + 4x^2

Combine like terms.

4x^2 – 4x + 5

Factor this equation. You will have to use the quadratic equation for this.

[-4 + or – root(16 – 80)]/4

That’s odd.. You can’t have a negative in a square root.. So therefore, this equation’s answer would be no solution because there is an imaginary number in it, I suppose..

3) 9x^2 + 2x + 5 – 5x^2 + 8x – 6

First of all, combine your like terms.

4x^2 + 10x – 1

Ooooh.. Looks like it’s going to be a toughie.. 😛 Saying that because you can’t factor it using standard..

First of all, plug the numbers into the quadratic equation.

[-10 + or – root(100 – 16)]/4

Okay, simplify it a little bit.

[-10 + or – root(84)]/4

You can extract 4 from 84. Lets do that.

[-10 + or – 2 root (21)]/4

YAY! Now you can get rid of that denominator! (Part of it)

[-5 + or – root(21)]/2

That’s your answer. You should check it just in case.

Hope I helped.

check your order of operations.. here goes

1) 6x[2] – 2X + 5X – 3 = 6x[2] +3X -3

This is because you are adding like terms… +5x and -2X which gives you +3X.. I dont think there is another possibility, factoring.. ??

2) 4x[2] -4x +5

10) -11x[3] + 8X[2] +X – 4