Math experts please help (algebra 2)…?
1. -y(to the 5 power) z ( to the 7 power)
over(devided)
y(squared) z(to the 5 power)
2.(a(cubed)b(cubed)) (ab)(squared by a negative 2, outside of the perenthesis)
3. 3a(5a(squared)b) (6ab(cubed)
4.2c(cubed) d(3c(squared)d(to the fifth power) )
over (devided)
30c(to the fourth power) d (squared)
5. (6x(squared) y(to the fourth power) )
over (devided) >Cubed
(3x(to the fourth power) y (cubed))
6. 30a-2b(to the negative 6 power)
over (devided)
60a-(to the 6 power) b (to the negative 8 power)
Favorite Answer
1) -y^5z^7/y^2z^5 so take the y^2 to the top (it becomes y^-2) and subtract the exponents 5-2=3 so you have y^3 now take the z^5 to the top (it becomes z^-5) and subtract the exponents 7-5=2 and you have z^2
You end up with y^3z^2 / 1 which equals y^3z^2 ANSWER
2) To get rid of the exponent outside the (), multiply it times the exponents of everything inside. It really means: (ab)(ab).
So: a^3b^3(ab)^2 =
a^3b^3(a^2b^2) = multiply and we get:
a^5b^5 ANSWER
See if you can do the rest on your own.
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