A few days ago
Math distance circle: I need help with a math problem?
The problem is: find the distance between the center of the circle ( x+ 2)^2 + y^2 = 36 and the point (1,3)
Top 3 Answers
A few days ago
Favorite Answer
In general the equation of a circle is (x-h)^2 + (y-k)^2 = r^2 with a center (h,k) and a radius r. In this problem the center of the circle is (-2,0). Now to find the distance between two points[(x1,y1) and (x2,y2)] you use the formula D=sqrt((x1-x2)^2 + (y1-y2)^2). So in this problem the distance between (-2,0) and (1,3) is 3*sqrt(2) [3 times the square root of 2]
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A few days ago
The formula for a circle that does not have its center at the origin is
(x – h)^2 + (y – k)^2 = r^2
So your equation tells me that the center of the circle is at (-2,0).
So you can use the distance formula to find that distance. d = sq rt [x(sub2) -x(sub1)]^2 + [y(sub2 – y(sub1)]^2
So d = (1- -2)^2 + (3 – 0)^2
d = 3^2 + 3^2 = 18
D= sq rt of 18 = 3 sq rt 2
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A few days ago
is that all it says?
it seems like it needs more info but it might be 18…
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