Math B2 help question.?

Help this is the only question on my hw im stuck on.

please tell me the process if possible.

The height of h, in feet, a ball will reach when thrown in the air is a function of time, t , in the seconds, given by the equation

h(t) = -16t(squared) +30t+6. Find, to the nearest tenth, the maximum height, in feet, the ball will reach.

and

Top 1 Answers

A few days ago

lloyd_taggart11

Favorite Answer

Pre-Cal answer:

This is a quadratic function (y = ax^2 + bx +c) so to find the max value, find the vertex.

t = -b/2a = -30/(2)(-16) = 0.9375s (time of max h)

h(0.9375) = -16(0.9375)^2 +30(0.9375) + 6 = 20.06ft

Calculus answer:

h'(t) = -32t +30

-32t +30 = 0

t = 0.9375s (critical pt)

h(0.9375) = -16(0.9375)^2 +30(0.9375) + 6 = 20.06ft

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