A few days ago
funj2007

Math B2 help question.?

Help this is the only question on my hw im stuck on.

please tell me the process if possible.

The height of h, in feet, a ball will reach when thrown in the air is a function of time, t , in the seconds, given by the equation

h(t) = -16t(squared) +30t+6. Find, to the nearest tenth, the maximum height, in feet, the ball will reach.

and

Top 1 Answers
A few days ago
lloyd_taggart11

Favorite Answer

Pre-Cal answer:

This is a quadratic function (y = ax^2 + bx +c) so to find the max value, find the vertex.

t = -b/2a = -30/(2)(-16) = 0.9375s (time of max h)

h(0.9375) = -16(0.9375)^2 +30(0.9375) + 6 = 20.06ft

Calculus answer:

h'(t) = -32t +30

-32t +30 = 0

t = 0.9375s (critical pt)

h(0.9375) = -16(0.9375)^2 +30(0.9375) + 6 = 20.06ft

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