A few days ago
Math B2 help question.?
Help this is the only question on my hw im stuck on.
please tell me the process if possible.
The height of h, in feet, a ball will reach when thrown in the air is a function of time, t , in the seconds, given by the equation
h(t) = -16t(squared) +30t+6. Find, to the nearest tenth, the maximum height, in feet, the ball will reach.
and
Top 1 Answers
A few days ago
Favorite Answer
Pre-Cal answer:
This is a quadratic function (y = ax^2 + bx +c) so to find the max value, find the vertex.
t = -b/2a = -30/(2)(-16) = 0.9375s (time of max h)
h(0.9375) = -16(0.9375)^2 +30(0.9375) + 6 = 20.06ft
Calculus answer:
h'(t) = -32t +30
-32t +30 = 0
t = 0.9375s (critical pt)
h(0.9375) = -16(0.9375)^2 +30(0.9375) + 6 = 20.06ft
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