A few days ago
k_artiaco

Last Math question I need help with?

A business consultant has developed a management training course. She has determined that her yearly profit in hundreds of dollars from selling and conduction the course is given by p(x)=-2x^2+60x-25. How many courses should she sell to maximize her profit? What is the maximum profit?

What do I do here? Thanks for any help that I can get..

Top 2 Answers
A few days ago
nekidasajaybird

Favorite Answer

Use the equation (-b)/(2a) to find the vertex of the parabola:

(-60)/[2(-2)]= -60/-4=15

She needs to sell 15 courses to maximize her profit.

Plug 15 back into your original equation:

p(15)= -2(15^2) + 60(15) -25

-2(225) + 900 – 25

-450 + 900 -25

425

Her maximum profit will be $425

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A few days ago
hayharbr
Algebraically, the maximum point onn a parabola with equation ax^2 + bx + c is found when x = -b/(2a)

So here x = -60/[2(-2)] = -60/-4 = 15

Then plug that in to get the maximum profit.

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