1. distribute the 7

7r + 49 = 5r + 59

2. subtract 5r from both sides

2r + 49 = 59

3. subtract 49 from both sides

2r = 10

4. divide both sides by 2

r = 5

for the check you just copy down the original problem but write 5 instead of r. then see if it works

here’s how to do the second problem:

1. distribute the 5 and the 3/5

5n + 10 = 3 + 6n

2. subtract 5n from both sides

10 = 3 + n

3. subtract 3 from both sides

7= n

there’s your answer!

Okay. You basically just combine things that are alike. Such as the 7 and the (r+7) since the seven is on the outside of the parenthesis, you must multiply the 7 by everything inside the parenthesis. Now, we all know that you cannot possibly multiply the number 7 with a variable or “n” in your case and come out with a number. So, basically you just link up the 7 and the r so it would be 7r. then the next part of the problem you can combine 7 & 7 by multiplying which would be 49. so so far, you have 7r + 49. then to the second part of the equation. you have a 5r which is in the same form as the 7r so you add them together which would end up to be 12r +49 [the 49 is from earlier] and now you can add 49 and 59 since they are also alike. Which would equal 108. So in the end, your problem will be 12r + 108. Which is simplified….

As for the other equation, since it has a fraction, i’m sorry, but I am unable to help you with that one. Please contact me at my email [email protected] if you need anymore help working out the first one…

Hope this was clear enough! =]]

Good luck,

Bri

7r+49=5r+59 (I multiplied 7xr and 7×7)

2r=10 (I subtracted 5r from 7r and 49 from 59)

r=5 (I divided 10 by 2)

5(n+2) = 3/5(5+10n)

This is ambiguous; it can be read two ways. I can read this as 3/{5(5+10n)} or (3/5)*(5+10n). Yeah, yeah, rules of multiplication order BS, that’s why we use parentheses in college to avoid ambiguity.

7r+49=5r+59

-5r -5r

2r+49=59

-49 -49

2r=10

divide by 10 on both sides

r=5

i dont feel like doing the other..

too much typing

7r+49=5r+59

7r-5r=59-49

2r=10

r=5

5n+10=3+6n

10-3=6n-5n

7=n

to check just put it back into the equation in place of the letter and see if it makes a true statement.

7r+49=5r+59

7r-5r=59-49

2r=10

r=5

5n+10=3+6n

10-3=6n-5n

7=n

7r-5r = 59-49

2r = 10

r=5

5n+10 = 3+6n

7 = n

7r+49=5r+59

isolate r

7r+49=5r+59

-5r -5r

2r+49=59

-49 -49

2r=10

— —

2 2

r= 5

now try the other… distribute, the isolate hope this helps…

7(r+7) = 5r+59

expand

7r+49 = 5r+59

collect like terms

7r-5r=59-49

2r=10

divide bothsides by 2

2r/2=10/2

r=5

2.

5(n+2)=3/5(5+10n)

5n+10=3/(25+50n)

cross multiply

5n+10(25+50n)=3

5n(25+50n)+10(25+50n)=3

125n+250n+250+500n=3

875n=3-250

875n=-247

divide b.s by 247

n=3.54