Ineqaulity..MATH QUESTION!?
x+3(x – 6) = -(x – 12) + 34
Favorite Answer
x+3(x – 6) = -(x – 12) + 34
=> x + 3x – 18 = -x + 12 + 34
=> 4x – 18 = -x + 46
next add 18 on both sides
=> 4x = -x + 64
next add the x on both sides
=> 5x = 64
divide both sides by 5
=> x = 12.8
// times 3 with (x-6)
x +3x-18 = -x+12 + 34
// add x with 3x you will get 4x then
4x – 18 = -x + 46
// Group x at one side
4x + x = 46 +18
5x = 64
x = 64/5
x = 12.8
khrome_wind : 12 + 34 is 46 not 36
x+3(x-6) = -(x-12)+34
x+(3x-(3*6)) = (-x-(-12))+34
x+3x-18 = -x+12+34
4x-18 = -x+46
4x+x = 46+18
5x = 64
x = 9
hope that will be help.thanks.! BTW work hard bro.u will find math is interesting than u thought.!
distribute the negative on right side and then mulitply by 3 on left side
x + 3x – 18 = -x + 12 +34
combine like terms
4x – 18 = -x + 46
add x to both sides
5x – 18 = 46
add 18
5x = 64
x = 64/5
x+3x-18 = -(x – 12) + 34
x+3x = -(x – 12) + 52
4x = -(x – 12) + 52
4x = -x + 12 + 52
4x = -x + 64
3x = 64
x = 64/3
x = 21.333
x+3x-18=-x+12+34
4x-18=-x+36
4x=-x+58
5x=58
x=10.8
x+3x+-6=-(x-12)+43
4x+-6=(x-12)+43
6 6
4x=(x-12)+49
x x
5x=-12+49
5x=37
5 5
x+7.4
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