If a line contains the points (4, 19) and (-3, 5), what is the slope of a line perpendicular to it?
Favorite Answer
1. find slope for the line AB, say m1
2. the slope of the line perpendicular to AB is
m2 = – 1/(m1)
tip: to find slope of line passing A(4,19) and B(-3,5)
slope m1= (yB -yA) / (xA – xB)
where
A(xA, yA) = A(4,19)
B(xB, yB) = B(-3,5)
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circle centered at the origin runs through the point (9, 12). What is the radius of the circle?
tip: radius of the circle at origin running through the point(x,y)
radius = sqrt(x^2, y^2)
radius = sqrt (9^2 + 12^2) = sqrt(81 + 144)
radius = sqrt(225) = 15
find the slope of line AB, then find the number that when the nunbers are multiplied, they equal -1.
2. 15
use the distance formula to find distance between center & origin .
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