i need help with solving 14x – 3(3x – 6) = 21 – x + 37 and 5x + 18 = 1/2(56 – 12x) + 26 + -7x?
Favorite Answer
For example-
14x -3(3x-6) -> 14x + (-3)(3x) + (-3)(-6)
-> 14x -9x + 18
-> 5x + 18
21 – x + 37 -> 21 + 37 – x
-> 58 -x
5x + 18 = 58 -x Add x to both sides
6x + 18 = 58 Isolate x by getting rid of the 18
6x = 58 – 18 -> 6x = 40
x = 40 /6, or 6 and 4/6
Now, try the second one yourself! Drop me a line if you REALLY need help.
14x-9x+18=58-x parenthesis and add 21 and 37
5x+18=58-x add 14x and -9
-18 -18 move the 18 to the other side
5x=40-x move the -x to the other side
+x +x
6x=40
6x/6=40/6 divide both sides by 6
x=6 2/3
2. 5x+18=1/2(56-12x)+26-7x
5x+18=28-6x+26-7x multiply 1/2 by everything in
5x+18=54-13x add like terms
+13x +13x move -13 to the other side
18x+18=54
-18 -18 move -18 to the other side
18x=36
18x/18=36/18 divide both sides by 18
x=2
14x-9x+16=21-x+37
6x=42
x=7
the second one
5x+18=28-6x+26+-7x
5x+18=54-13x
18x=36
x=2
Combine like terms
Isolate the variable (whatever you do to one side of the equation, you must do to the other)
14x-9x+18-=21-x+37
5x+18=58-x
6x+18=58
6x=40
x=40/6
x=20/3
x=6.666667
5x+18=.5(56-12x)+26
5x+18=28-6x+26-7x
5x+18=54-13x
18x+18=54
18x=36
x=2
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