I need help with my algebra homework. Can you help me please?
The perimeter of a triangle is 51 cm. The measure of the smallest side is 4 less than the middle side. The measure of the longest side is equal to one less than the sum of the other sides. Find the lengths of the sides.
Favorite Answer
Let m represent the length of the middle side:
The short side is: m – 4
The long side is: (m + m -4) – 1
The perimeter is: m + (m – 4) + (m + m – 4) – 1 = 51
Simplify: 2m – 4 + 2m – 4 – 1 = 51
Collect like terms:
4m = 51 + 9 = 60
m = 15
Proof:
Small side is: 11, Middle side is 15, Long side is: 11 + 15 -1.
Perimeter is: 11 + 15 + 25 = 51 which was given.
So the three sides are x, x+4 and [x + (x+4)]-1. Together, they equal 51, so now you can solve for x, and use that value to find the length of the other two sides.
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