Ans:

First find the derivative of the equation:

i.e dy/dx = 3x^2 – 2x

where dy/dx = m = 3

therefore:

3 = 3x^2 – 2x

divide 3 on both sides

1= x^2 – 2x/3

using completing the square method

10/9 = x^2- 2x/3 + 1/9

(x-1/3)^2 = 10/9

x-1/3 = ±square root of 10/9

there fore x = [1±square root of 10] / 3

* to find y, substitute the value of x above in the original equation.

4. y = x^2+3 / 2x^2 where m = 3

This is the an example of finding the derivative of the quotient of two functions.

therefore first find the derivative.

dy/dx = [ (2x^2)2x – (x^2+3)4x ] / 4x^4

= [4x^3 – 4x^3 -12x] / 4x^4

= -12x/4x^4

= -3/x^3

where dy/dx = 3 = m

therefore:

3 = -3/x^3

solve from there on…

3. y=(4-x) / x is also like your question 4.

find the derivative of the quotient.

To help you on finding the derivative, use the following equations:

Contact me on vazel_dano@ yahoo.com if you want the formulaes for finding the derivative of functions.