2. Write an equation. Therefore the 6% amount is 8000-A

A*4/100 + (8000-A)*6/100 = 460 interest

3. Solve this equation (step by step).

4A/100 + (48000-6A)/100 = 460

Multiply by 100:

4A + 48000-6A = 46000

Collect like terms on opposite sides:

48000-46000 = 6A-4A

2000 = 2A

A = 1000

4. Answer the original question asked.

Kevin had $1000 in 4% account, $7000 in 6% account.

1 equation:

x = amount in account x

equation is

.04x + .06(8000 – x) = 460 distribute

.04 + 480 – .06x = 460 combine like terms

-.02x + 480 = 460 subtract 480

-.02x = -20 divide

x = 1000

so account x has 1000 and account has 8000-1000 or 7000

with 2 equations:

x is account x

y is account y

2 equation

.04x + .06y = 460

x + y = 8000

times top equation by 100

4x + 6y = 46000

x + y = 8000 times bottome equation by -4

4x + 6y = 46000

-4x – 4y = -32000 add straight down

2y = 14000 divide

y = 7000 (amount in account y )

so x has 1000

Assuming it’s right at the beginning, the variable represents the unknown quantity. What datum do you need to know, that has no specific value given in the problem description?