How do you subtract whole numbers with mixed fractions (16-8 3/8)?
Favorite Answer
using your problem, we could do it like this:
16 – 8 3/8 =
[(16*8) – (8*8+3)]/8 = and you can work that out the rest of the way
or (in excruciating detail)
16 – 8 3/8 =
16-8-3/8=
8-3/8 =
7+1-3/8 =
7+8/8-3/3
7+(8-3)/8 =
7 5/8
(you should be able to do all those steps in your head quicker than you can write just the problem)
So it the question is 5 – 4 1/4
Turn it into 5-4.25
Or in the case of your question, put the 16 over 1, make the mixed into an improper and find a common demonimator
Then change 8 3/8 into an improper fraction:
8 x 8= 64. 64+3=67.
so its 67/8
so now you do 16 minus 67/8.
and subtract the fractions and then the #s
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