how do you solve this fairly simple math problem?
2x – 3y = –2
4x + y = 24
Favorite Answer
4x + y = 24
then y = 24- 4x
So now I can substitute 24-4x in for y in the problem above.
2x – 3 (24 – 4x) = -2
2x – 72 + 12x = -2
14x – 72 = -2
14 x = 70
x = 5
Then you can substitute 5 in for x in the original problem.
4x + y = 24
4 (5) + y = 24
20 + y = 24
y = 4
So x = 5 and y = 4
You can cancel one of the variables by multiplying one and making it cancel when you add the two equations. In this case it is easier to multiply the second one by 3 to cancel y, but you could also multiply the first equation by -2 to cancel x
Step 1: 2x-3y=-2 (stays the same)
12x+3y= 72 (result of equation multiplied by 3)
Step 2: 14x=70 (result of adding the equations)
Step 3: x=70/14 (divide both sides by 14)
x=5
Step 4: Choose one equation and substitute x
2(5)-3y=-2
10-3y=-2 (Multiply)
-3y=-12 (subtract -10 to both sides)
y=-12/-3 (divide both sides by -3)
y=4 (positive because negative divided by
negative becomes positive)
So your answers are x=5, y=4
-2(2x-3y)=-2(-2)
You get:
-4x-6y=4
4x+y=24
Add the x’s together. -4x + 4x = 0. You are the left with:
6y=4
y=24
Add the y’s and 4+24
7y=28
Divide both sides by 7.
y=4
Now plug in 4 for any of the y values. We’ll pick the bottom line, since it’s easier.
4x + y = 24
becomes
4x + 4 = 24
Subtract 4 from both sides.
4x = 20
Divide both sides by 4
x = 5
So your answers are (5,4)
4x +y = 24 — eqn2
let eqn 2 – 2(eqn 1),
(4x + y) – 2(2x – 3y)= 24 – 2(-2)
7y = 28
y = 4 — eqn 3
sub eqn 3 to eqn 2,
4x + y = 24
4x = 24 – y
=24 – (4)
=20
x = 5
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