A few days ago
How do you solve these 2 systems of inequalities using graphing?
lxl<(or equal too) 3
lyl>1
and the two l’s are absolute valuse bars fyi.
and
y>x-3
lyl< (or equal too) 2 I understand how to graph and shade and stuff but how do you do the absolute value?
Top 3 Answers
A few days ago
Favorite Answer
Absolute value is really quite simple once you get it. All it means is distance without a + or – direction.
You can write |x|<=3 as -3<= x <= 3 Or, |y| <=2 as -2 <= y <= 2 Think of taking two steps away from a spot on the floor. Abs value just means that you are two steps away and ignores the actual direction you've moved in.
0
A few days ago
you would shade the x-area between +3 and -3
where the y-area is above +1 and below -1
The area is that has X values when the absolute vale is less than or equal to 3.
in the second problem,
you should already know to shade the y-area above the line y=x-3, but only the x-area between +2 and -2
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4 years ago
for a million and a couple of you ought to graph them, substitute them to y=3x-6 and y=2-x. Then the place the two lines bypass is the respond, in the event that they bypass at (3,4) that is one answer for substitution y=3, then positioned this into first one 3=5x-7 upload the two equations? uncertain? final one, draw, yet use dotted lines, then colour above or under the line (i exploit guess and attempt to ensure which factor)
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