A few days ago
How do I solve this math problem?
find cos θ by using pythagorean identity, sin^2 θ + cos^2 θ = 1
sin θ = 7/8
Top 4 Answers
A few days ago
Favorite Answer
You open your book and figure it out on your own. he he he he
I miss you baby
Kisses
0
A few days ago
if sin Î = 7/8, then
sin^2 Î = 49/64
and if sin^2 Î + cos^2 Î = 1, then
49/64 + cos^2 Î = 1
cos^2 Î = 1 – 49/64 = 15/64
so if cos^2 Î = 15/64 then
cos Î = â15 /8
0
A few days ago
(7/8)^2 + cos^2 q = 1
49/64 + cos^2 q = 1
cos^2 q = 15/64
cos q = +/- sqrt(15)/8
1
A few days ago
(sinθ)^2 +(cosθ )^2 = 1 ===> (cosθ )^2 = 1-(sinθ)^2
Since, sin θ = 7/8
===> (cosθ )^2 = 1-(49/64) = 15/64
===> cosθ = sqrt (cosθ)^2 = sqrt(15)/8
Hope i am right 🙂
0
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