A few days ago

JUST DU IT

How do i find ((x-8) ^2)/9 + ((y+3)^2)/9 =1?

i need help doing this problem if anyone can guide me the problem is ((x-8) ^2)/9 + ((y+3)^2)/9 =1

Top 3 Answers

A few days ago

Mitch

Favorite Answer

((x – 8) ^2) / 9 + ((y + 3)^2) / 9 = 1

Multiply both sides by 9, which leaves you:

(x – 8) ^2 + (y + 3) ^2 = 9

Now, take the square root of both sides:

(x – 8) + (y + 3) = +/- 3

(Remember, when taking the square root of 9, it is +/- 3)

Solve for y:

(x – 8) + (y + 3) = +/- 3

x – 8 + y + 3 =+/- 3

y = -x + 8 and y = -x + 2

Good luck in your studies,

~ Mitch ~

P.S. – I believe that’s the form your looking for, right?

If not, please add a note to the question. – Thanks.

A few days ago

sayamiam

this is the equation of a circle with a center at (8, -3)

the radius is 3

so when you solve for y you get:

y = -x + 8

y = -x + 2

A few days ago

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