A few days ago
Anonymous

How do I factor problems like the following.?

1) 9x^2y^3 -3x^y3^2 -15xy

2)2x^2y-4xy-30y

Please explain answers

Top 2 Answers
A few days ago
Mutou Kazuki

Favorite Answer

I think you wrote the first one wrong.

Anyway. What exactly do you mean by factoring?

Do you want to just “pull out” a variable?

Or do you ean synthetic division?

For synthethic division (the polynomial form of old school long division) you need to look it up in your book and WRITE out the examples as you follow the examples.

I’m not sure if those are the exact equations you want worked in 2x to the 2y-4xy-30y power…I’ve never ever seen something as convoluted as that in any of my math classes.

normal factoring is pul out variabls and combining exponents.

For example

9x^2y3 = (9x^y3)^2

2x^2y * 2x^(-4xy) * 2x^30y

= 2x^(2y-4xy-30y)

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A few days ago
navy_bison
Look for a common factor

1) 9x^2y^3 -3x^y3^2 -15xy

3xy(3xy^2 – x^2y – 5) then factor using your method of choice

2) 2x^2y – 4xy – 30y

2y(x^2 – 2x – 15) factor from here

Good starter to these. DOuble check how you inputed your first question it doesn’t make sense 3x^y3^2 unless you are rasing x to the y power.

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