A few days ago
help with triangles?
give a right triangle with b=4 and c=11 find a approximated to 3 decimal places
Top 5 Answers
A few days ago
Favorite Answer
Assuming that side a is the hypotenuse (opposite the right, or 90 degree angle) then the answer is the square root of the square of 4 plus the square of 11.
4 squared = 16
11 squared = 121
16 + 121 = 137
square root of 137 = 11.705
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A few days ago
The pythagorean theorem states that the sum of the squares of the legs of a right triangle equals the square of the hypotenuse. In other words, you can write this as a^2+b^2=c^2
For this triangle, you know the hypotenuse and one leg, so you can rewrite the equation like this:
a^2=c^2-b^2
121-16=a^2
105=a^2
the (positive) square root of 105 is approximately equal to 10.247
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A few days ago
a^2 + b^2 = c^2, Buy a calculator and do the math.
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A few days ago
i hate math
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A few days ago
It is exactly 2.471
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