A few days ago
Likhitha

Help…..with this problem plz?

A basketball falls from a height of 10m and bounces to 3/5 of its previous height. What is the highest height reached by the ball after the 4th bounce?

Top 2 Answers
A few days ago
Anonymous

Favorite Answer

The heights reached by the ball form a geometric progression. Its first term is 10*(3/5)=6 and its common ration is (3/5).

n-th term of the progression is given by:

a_n = 6*(3/5)^(n-1) = 10*(3/5)^n

In particular, the 4th term (the highest height reached by the ball after the 4th bounce) is:

a_4 = 10*(3/5)^4 = 10*(81/625) = 1.296 m

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A few days ago
hogwarts student
1st bounce – 6m

2nd bounce – 3.6m

3rd bounce – 2.16m

4th bounce – 1.296m

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