A few days ago
Help…..with this problem plz?
A basketball falls from a height of 10m and bounces to 3/5 of its previous height. What is the highest height reached by the ball after the 4th bounce?
Top 2 Answers
A few days ago
Favorite Answer
The heights reached by the ball form a geometric progression. Its first term is 10*(3/5)=6 and its common ration is (3/5).
n-th term of the progression is given by:
a_n = 6*(3/5)^(n-1) = 10*(3/5)^n
In particular, the 4th term (the highest height reached by the ball after the 4th bounce) is:
a_4 = 10*(3/5)^4 = 10*(81/625) = 1.296 m
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A few days ago
1st bounce – 6m
2nd bounce – 3.6m
3rd bounce – 2.16m
4th bounce – 1.296m
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