help!!!!! with geometry problem!!!!! please!!!!!?
(find the following)
If angleBOF= 120, then angleDOE=_____
If angleCOG= 35, then angleEOG= _____
PLEASE HELP ME!!!!!!!! I DONT GET IT…. ):
Favorite Answer
That means 1/2angleAOB=angleAOC=angleCOB
rayOD bisects angleAOC:
that means 1/2angleAOC=angleAOD=angleDOC
rayOE bisects angle AOD:
that means 1/2angleAOD=angleAOE=angleEOD
rayOF bisects angle AOE:
that means 1/2angleAOE=angleAOF=angleFOE
rayOG bisects angle FOC:
that means 1/2angleFOC=angleFOG=angleGOC
let x=angleAOF=angleFOE
then 2x=angleAOE=angleEOD
then 4x=angleAOD=angleDOC
then 8x=angleAOC=angleCOB
120 = angleBOF= angleFOB =
angleFOE + angleEOD + angleDOC + angleCOB
120 = x + 2x + 4x + 8x
120 = 15x
8 = x
angleDOE = angle EOD = 2x = 16
if angle COG=35, the angleEOG=?
rayOG bisects angleFOC,
that means 1/2angleFOC=angleFOG=angleGOC
angleFOC= angleFOE + angleEOD + angleDOC
angleFOC= x + 2x + 4x = 7x
and
angleFOG=angleGOC=3.5x
angleEOG = angleEOB -(angleGOC+angleCOB)
angleEOG = (angleEOC+angleCOB) -(3.5x+angleCOB)
angleEOG = (angleEOC-3.5x) + (angleCOB-angleCOB)
angleEOG = (angleEOD+angleDOC-3.5x)
angleEOG = (2x+4x – 3.5x)= 2.5x = 2.5(8) = 20
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