A few days ago
help solve a maths differentiation qn please!?
y= [ x^2 ] [(cos 3x )^2]
can someone help to differentiate this for me?
I tried but my ans looks weird.
Top 2 Answers
A few days ago
Favorite Answer
([x^2][(cos 3x)^2])’
= [x^2]'(cos 3x)^2 + (x^2)[(cos 3x)^2]’
= 2x (cos 3x)^2 + (x^2) * 2 * (cos 3x)’ cos(3x)
= 2x (cos 3x)^2 – 2 x^2 (3x)’ sin(3x) cos(3x)
= 2x (cos 3x)^2 – 6 x^2 sin(3x) cos(3x)
0
A few days ago
dy/dx = 2x * (cos(3x))^2 – [2x^2] * [sin(3x)]
i think of these problems like this:
break into 2 parts like this: x^2 and [(cos 3x )^2]
then i say: front times the derivative of the back to get: -[2x^2] * [sin(3x)]
plus back times the derivative of the front: 2x * (cos(3x))^2
0
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