help on physics?
2.Doug wants to weigh his puppy, but does not have a scale available. Remembering the concept of torque from his physics class, he suspends a uniform 2m long rod from a rope in such a way that the rod is balanced. He places the puppy in a mesh bag and carefully hangs the bag from one end of the rod. He then places a 5lb (22.24N) bag of sugar in another bag and suspends it from the side of the rod opposite the puppy. He finds that the rod is balanced when the bag of sugar is a distance of 0.65m from the pivot. How much does the puppy weigh?
Favorite Answer
http://en.wikipedia.org/wiki/Dimensional_analysis
Units for torque are distance & Force – i.e. Ft-lbf, N-m, etc.
For your problem, the system will be in equilibrium when the FxD on both sides are equal…
Puppy Wt * 1m = 22.241N * 0.65m …. So:
Puppy Wt = ( 22.241N * 0.65m ) / 1 m = 14.457 N = 3.25 lbf
2. Do the math yourself!
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