A few days ago
Help me please…?
slope of the tangent line to the graph of the exponential function y = 2^x at the point (0,1) is given as:
lim x-> 0
((2^x)-1)/x
Estimate slope to 3 decimal places.
any help would be GREAT!
Top 1 Answers
A few days ago
Favorite Answer
If both the numerator and the denominator tend to zero when x approaches zero, you have to use “De L’ H^opital” ‘s rule, which means that you have to find the fraction of the derivatives (=graph slopes) of the numerator and the denominator, respectively.
Think cleverly: [Talking about limits at the given point]
If (2^x)’ = (2^x -1)/x, then (2^x -1)’ = (2^x)’ -1′ = (2^x)’.
Doing the rest of the work gives you a typical function, which you can use to get the result you want.
If I am wrong, I am deeply ashamed of myself.
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