A few days ago
Nextgen89

hard college math question…… Consider a square building with one of the sides being 8ft long….?

My partner in my group might not have done his problem and we have to turn it in in 2 hours! So this will help back my gorup up.

Consider a square building with one of the sides being 8 feet long. There is a storm that produces rain at a rate of 1/2 inch per hour. The building has one down spout that can drain 250 gallons of water per hour.

a. How much falls on the roof of the building in one hour in cubic inches?

b.Use the fact that 1 gallon is equal to about 231 cubic inches, write a function in terms of x that relates the amount of water in gallons that lands on the roof in x hours.

c. How many gallons of rain landed on the roof in 3.5 hours?

Top 2 Answers
A few days ago
John V

Favorite Answer

8 feet = 96 inches, so area = 9216 sq in.

area * .5 = 4608 cu. in/hr. This is 19.95 gallons.

C(x) = 19.95x

C(3.5) = 69.8 gallons.

This ignores the fact that the water will drain completely via the spout.

0

A few days ago
Paige
Okay, I might be wrong, but here is how I interpret the problem:

1. First, since the building is square, the roof will be 8ft x 8ft, or 96in x 96in. If there is 1/2inch rainfall in hone hour, the amount of rain on the roof will be 96in x 96 in x 1/2 in or 4608 cubed inches.

2. So first we know that the roof is 9216 sq in (96in x 96in). And there is 1/2 in per hour. the Cubic inches equation is with x being the number of hours:

(9216 sq in) X (.5in/hr)(x) = amnt of water that land on roof in cubic in.

Change that into gallons::

(1gal/231cubic in) (9216 sq in) X (.5in/hr)(x) = amnt of water that land on roof in gallons.

-the cubic in on the bottom will cancel with the sq in x in to leave galons.

3. Plug in 3.5 into the last equation:

(1gal/ 231 cubic in)(9216 sq in) X (.5in/hr)(3.5hr) = 62.82 gal

I hope that’s right or at least helps. Have fun in class!

0