Graph absolute inequality |x-3y|>=9?

this is the work i’ve done so far to solve it”

-9>= x – 3y >= 9

+3 +3 +3

-6>= x – y >= 12

That’s as far as I got…am I on the right track?

Top 2 Answers

A few days ago

Anonymous

Favorite Answer

Your first step is almost right, but adding 3 to -3y does not give you -y. The 3 in 3y is multiplicative, not additive.

You’re going to need two lines:

x – 3y = 9

and

x – 3y = -9

Graph those – that will cut the coordinate plane into four quadrants. One or more of those four quadrants will be your answer. The “approved” method of figuring out which it is is to graph the solution of x – 3y >= 9 and the solution set of x – 3y >= -9 and then looking for where they overlap. The easier way it to pick points in all four quadrants – shade the ones where the point works in the original inequality.

4 years ago

sandigo

initially supply x=0 then y>2; supply y=0 then x>3; take the bigger areas of x=3 apsis(perfect area of x=3); and take the better area of y=2 oordinat; the relationship element of those areas is your answer. for x=0 ; y=-a million for y=0; x=-a million/3 now u ought to draw a line which passes by y=-1and x=-a million/3 . your answer is the section which s betveen coordinat gadget and your line.(it s a triangle)

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Graph absolute inequality |x-3y|>=9?

Graph absolute inequality |x-3y|>=9?

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