FORmula question..PLZ help!?
If the percentage composition is given, assume a 100g sample make sure you have whole number coefficients
I tried this n received the final formula numbers to be 13.56, 19.16, 1 , 1.9575 for C, H, N, O respectively…is tht correct? hw do I round up the numbers though????
Favorite Answer
C: 71.34/12.01 = 5.94x
H: 8.43/1.008 = 8.36x
N: 6.16/14.01 = 0.440x
O: 14.07/16.00 = 0.879x
The number for N is smallest, and there has to be at least 1 atom of nitrogen, so guess that x = 1/0.440 and multiply everything by that:
C: 13.5 (roughly)
H: 19
N: 1
O: 2
These are very near whole numbers, except for C the result is very near a whole number plus1/2. So multiply everything by 2 to get
C: 27 atoms
H: 38
N: 2
O: 4
This is probably the simplest formula. To check, multiply the numbers by the atomic weights and take percentages to see if you get the original composition.
C14H19NO2
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