A few days ago
find the vertex and the axis of symmetry of x=y^2-6y+14?
find the vertex and the axis of symmetry of x=y^2-6y+14?
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A few days ago
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x = ay^2 + by + c
To find axis of symmetry: y = -b/2a
Axis of symmetry: y = 6
Vertex: (substitute y = 6 into the equation to find the x-value)
x = 36 – 36 + 14 = 14
Therefore, vertex is (14,6)
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