Find the sum of the first n terms of the geometric series…show work please?

1 + 4 + 16 + 64

n=14

Top 1 Answers

A few days ago

MsMath

Favorite Answer

Note that

1 = 4^0

4 = 4^1

16 = 4^2

64 = 4^3

This is the sum of (4^k), from k = 0 to 14

The formula for the sum of the first n terms of

ar^k, when k starts at 0 is

a(1 – r^(n+1)) / (1-r)

a = 1, r = 4, and n = 14

Plug those into the formula.

1(1 – 4^(14+1)) / (1-4)

= (1 – 4^15) / (-3)

= (1 – 1,073,741,824) / (-3)

= -1,073,741,823 / (-3)

= 357,913,941

science project?

need an example of work cited and bibliograophy for paper?

Home work help!!!?

My son needs help with math…I am not good with math..HELP?

what is the slope of the line passing through the given points (4,5),(2,9)?

Help with Substition method?

Vertebrates and Invertebrates?

Solve the following equation for the variable x?